-[2](1[y-5]1)=4y+40

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Solution for -[2](1[y-5]1)=4y+40 equation:


Simplifying
-1[2](1[y + -5] * 1) = 4y + 40

Reorder the terms:
-1 * 2(1[-5 + y] * 1) = 4y + 40

Reorder the terms for easier multiplication:
-1 * 2(1 * 1[-5 + y]) = 4y + 40

Multiply 1 * 1
-1 * 2(1[-5 + y]) = 4y + 40
-1 * 2([-5 * 1 + y * 1]) = 4y + 40
-1 * 2([-5 + 1y]) = 4y + 40

Multiply -1 * 2
-2(-5 + 1y) = 4y + 40
(-5 * -2 + 1y * -2) = 4y + 40
(10 + -2y) = 4y + 40

Reorder the terms:
10 + -2y = 40 + 4y

Solving
10 + -2y = 40 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
10 + -2y + -4y = 40 + 4y + -4y

Combine like terms: -2y + -4y = -6y
10 + -6y = 40 + 4y + -4y

Combine like terms: 4y + -4y = 0
10 + -6y = 40 + 0
10 + -6y = 40

Add '-10' to each side of the equation.
10 + -10 + -6y = 40 + -10

Combine like terms: 10 + -10 = 0
0 + -6y = 40 + -10
-6y = 40 + -10

Combine like terms: 40 + -10 = 30
-6y = 30

Divide each side by '-6'.
y = -5

Simplifying
y = -5

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